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Fix lexing of 'case' in do...done in a $(comsub) (rhbz#1241013)

The following caused a spurious syntax error:

$ x=$(for i in 1; do case $i in word) true;; esac; done)
-ksh: syntax error: `;;' unexpected

Prior discussion:
https://bugzilla.redhat.com/1241013

Original patch, backported from 93v- beta, applied without change:
642af4d6/f/ksh-20120801-parserfix.patch
This commit is contained in:
Martijn Dekker 2020-09-27 21:26:09 +02:00
parent bb15f7fb19
commit bd283959be
4 changed files with 27 additions and 1 deletions

9
NEWS
View file

@ -3,6 +3,15 @@ For full details, see the git log at: https://github.com/ksh93/ksh
Any uppercase BUG_* names are modernish shell bug IDs.
2020-09-27:
- The shell's lexical analisys of a 'case' statement within a do...done block
within a command substitution of the form $(...) has been fixed so that code
like the following no longer throws a spurious syntax error:
x=$(for i in 1; do case $i in word) true;; esac; done)
Previously, this required a leading parenthesis before 'word', although the
syntax error claimed that the ';;' was unexpected.
2020-09-26:
- 'whence -f' now completely ignores the existence of functions, as documented.