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Check passwds hashed w/ 'yescrypt' etc too, in /etc/shadow

This commit is contained in:
root 2021-08-28 22:16:03 -04:00
parent fa928289fa
commit 029778139b
2 changed files with 22 additions and 12 deletions

View file

@ -24,12 +24,17 @@ check_user_pwd() {
# (read access to /etc/shadow is otherwise restricted to just root and # (read access to /etc/shadow is otherwise restricted to just root and
# group www-data i.e. Apache, NGINX get special access). SEE: #2431, #2561 # group www-data i.e. Apache, NGINX get special access). SEE: #2431, #2561
# $meth (hashing method) is typically '6' which implies 5000 rounds # 2021-08-28: New OS's use 'yescrypt' so use Perl instead of Python (#2949)
# of SHA-512 per /etc/login.defs -> /etc/pam.d/common-password # This also helps avoid parsing the (NEW) 4th sub-field in $y$j9T$SALT$HASH
meth=$(sudo grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f2) field2=$(grep "^$1:" /etc/shadow | cut -d: -f2)
salt=$(sudo grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f3) [[ $(perl -e "print crypt('$2', '$field2')") == $field2 ]]
hash=$(sudo grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f4)
[ $(python3 -c "import crypt; print(crypt.crypt('$2', '\$$meth\$$salt'))") == "\$$meth\$$salt\$$hash" ] # # $meth (hashing method) is typically '6' which implies 5000 rounds
# # of SHA-512 per /etc/login.defs -> /etc/pam.d/common-password
# meth=$(sudo grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f2)
# salt=$(sudo grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f3)
# hash=$(sudo grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f4)
# [ $(python3 -c "import crypt; print(crypt.crypt('$2', '\$$meth\$$salt'))") == "\$$meth\$$salt\$$hash" ]
} }
#grep -q "^PasswordAuthentication\s\+no\b" /etc/ssh/sshd_config && return #grep -q "^PasswordAuthentication\s\+no\b" /etc/ssh/sshd_config && return

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@ -23,12 +23,17 @@ check_user_pwd() {
# enough when user does not exist. Or uncomment to FORCE ERROR CODE 2. # enough when user does not exist. Or uncomment to FORCE ERROR CODE 2.
# Either way, overall bash script still returns exit code 0 ("success"). # Either way, overall bash script still returns exit code 0 ("success").
# $meth (hashing method) is typically '6' which implies 5000 rounds # 2021-08-28: New OS's use 'yescrypt' so use Perl instead of Python (#2949)
# of SHA-512 per /etc/login.defs -> /etc/pam.d/common-password # This also helps avoid parsing the (NEW) 4th sub-field in $y$j9T$SALT$HASH
meth=$(grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f2) field2=$(grep "^$1:" /etc/shadow | cut -d: -f2)
salt=$(grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f3) [[ $(perl -e "print crypt('$2', '$field2')") == $field2 ]]
hash=$(grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f4)
[ $(python3 -c "import crypt; print(crypt.crypt('$2', '\$$meth\$$salt'))") == "\$$meth\$$salt\$$hash" ] # # $meth (hashing method) is typically '6' which implies 5000 rounds
# # of SHA-512 per /etc/login.defs -> /etc/pam.d/common-password
# meth=$(grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f2)
# salt=$(grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f3)
# hash=$(grep "^$1:" /etc/shadow | cut -d: -f2 | cut -d$ -f4)
# [ $(python3 -c "import crypt; print(crypt.crypt('$2', '\$$meth\$$salt'))") == "\$$meth\$$salt\$$hash" ]
} }
# 2020-10-13 https://github.com/iiab/iiab/issues/2561 RECAP: Above was blocking # 2020-10-13 https://github.com/iiab/iiab/issues/2561 RECAP: Above was blocking