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			244 lines
		
	
	
	
		
			5.7 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			244 lines
		
	
	
	
		
			5.7 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
/*
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 * Copyright 2011-2018 The OpenSSL Project Authors. All Rights Reserved.
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 *
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 * Licensed under the OpenSSL license (the "License").  You may not use
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 * this file except in compliance with the License.  You can obtain a copy
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 * in the file LICENSE in the source distribution or at
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 * https://www.openssl.org/source/license.html
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 */
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#include <stdio.h>
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#include <openssl/bn.h>
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#include "bn_local.h"
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/* X9.31 routines for prime derivation */
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/*
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 * X9.31 prime derivation. This is used to generate the primes pi (p1, p2,
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 * q1, q2) from a parameter Xpi by checking successive odd integers.
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 */
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static int bn_x931_derive_pi(BIGNUM *pi, const BIGNUM *Xpi, BN_CTX *ctx,
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                             BN_GENCB *cb)
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{
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    int i = 0, is_prime;
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    if (!BN_copy(pi, Xpi))
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        return 0;
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    if (!BN_is_odd(pi) && !BN_add_word(pi, 1))
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        return 0;
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    for (;;) {
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        i++;
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        BN_GENCB_call(cb, 0, i);
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        /* NB 27 MR is specified in X9.31 */
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        is_prime = BN_is_prime_fasttest_ex(pi, 27, ctx, 1, cb);
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        if (is_prime < 0)
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            return 0;
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        if (is_prime)
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            break;
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        if (!BN_add_word(pi, 2))
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            return 0;
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    }
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    BN_GENCB_call(cb, 2, i);
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    return 1;
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}
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/*
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 * This is the main X9.31 prime derivation function. From parameters Xp1, Xp2
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 * and Xp derive the prime p. If the parameters p1 or p2 are not NULL they
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 * will be returned too: this is needed for testing.
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 */
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int BN_X931_derive_prime_ex(BIGNUM *p, BIGNUM *p1, BIGNUM *p2,
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                            const BIGNUM *Xp, const BIGNUM *Xp1,
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                            const BIGNUM *Xp2, const BIGNUM *e, BN_CTX *ctx,
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                            BN_GENCB *cb)
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{
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    int ret = 0;
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    BIGNUM *t, *p1p2, *pm1;
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    /* Only even e supported */
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    if (!BN_is_odd(e))
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        return 0;
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    BN_CTX_start(ctx);
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    if (p1 == NULL)
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        p1 = BN_CTX_get(ctx);
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    if (p2 == NULL)
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        p2 = BN_CTX_get(ctx);
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    t = BN_CTX_get(ctx);
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    p1p2 = BN_CTX_get(ctx);
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    pm1 = BN_CTX_get(ctx);
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    if (pm1 == NULL)
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        goto err;
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    if (!bn_x931_derive_pi(p1, Xp1, ctx, cb))
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        goto err;
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    if (!bn_x931_derive_pi(p2, Xp2, ctx, cb))
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        goto err;
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    if (!BN_mul(p1p2, p1, p2, ctx))
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        goto err;
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    /* First set p to value of Rp */
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    if (!BN_mod_inverse(p, p2, p1, ctx))
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        goto err;
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    if (!BN_mul(p, p, p2, ctx))
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        goto err;
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    if (!BN_mod_inverse(t, p1, p2, ctx))
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        goto err;
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    if (!BN_mul(t, t, p1, ctx))
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        goto err;
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    if (!BN_sub(p, p, t))
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        goto err;
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    if (p->neg && !BN_add(p, p, p1p2))
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        goto err;
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    /* p now equals Rp */
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    if (!BN_mod_sub(p, p, Xp, p1p2, ctx))
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        goto err;
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    if (!BN_add(p, p, Xp))
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        goto err;
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    /* p now equals Yp0 */
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    for (;;) {
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        int i = 1;
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        BN_GENCB_call(cb, 0, i++);
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        if (!BN_copy(pm1, p))
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            goto err;
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        if (!BN_sub_word(pm1, 1))
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            goto err;
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        if (!BN_gcd(t, pm1, e, ctx))
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            goto err;
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        if (BN_is_one(t)) {
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            /*
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             * X9.31 specifies 8 MR and 1 Lucas test or any prime test
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             * offering similar or better guarantees 50 MR is considerably
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             * better.
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             */
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            int r = BN_is_prime_fasttest_ex(p, 50, ctx, 1, cb);
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            if (r < 0)
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                goto err;
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            if (r)
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                break;
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        }
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        if (!BN_add(p, p, p1p2))
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            goto err;
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    }
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    BN_GENCB_call(cb, 3, 0);
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    ret = 1;
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 err:
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    BN_CTX_end(ctx);
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    return ret;
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}
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/*
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 * Generate pair of parameters Xp, Xq for X9.31 prime generation. Note: nbits
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 * parameter is sum of number of bits in both.
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 */
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int BN_X931_generate_Xpq(BIGNUM *Xp, BIGNUM *Xq, int nbits, BN_CTX *ctx)
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{
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    BIGNUM *t;
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    int i;
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    /*
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     * Number of bits for each prime is of the form 512+128s for s = 0, 1,
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     * ...
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     */
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    if ((nbits < 1024) || (nbits & 0xff))
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        return 0;
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    nbits >>= 1;
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    /*
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     * The random value Xp must be between sqrt(2) * 2^(nbits-1) and 2^nbits
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     * - 1. By setting the top two bits we ensure that the lower bound is
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     * exceeded.
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     */
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    if (!BN_priv_rand(Xp, nbits, BN_RAND_TOP_TWO, BN_RAND_BOTTOM_ANY))
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        goto err;
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    BN_CTX_start(ctx);
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    t = BN_CTX_get(ctx);
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    if (t == NULL)
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        goto err;
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    for (i = 0; i < 1000; i++) {
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        if (!BN_priv_rand(Xq, nbits, BN_RAND_TOP_TWO, BN_RAND_BOTTOM_ANY))
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            goto err;
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        /* Check that |Xp - Xq| > 2^(nbits - 100) */
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        if (!BN_sub(t, Xp, Xq))
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            goto err;
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        if (BN_num_bits(t) > (nbits - 100))
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            break;
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    }
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    BN_CTX_end(ctx);
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    if (i < 1000)
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        return 1;
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    return 0;
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 err:
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    BN_CTX_end(ctx);
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    return 0;
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}
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/*
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 * Generate primes using X9.31 algorithm. Of the values p, p1, p2, Xp1 and
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 * Xp2 only 'p' needs to be non-NULL. If any of the others are not NULL the
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 * relevant parameter will be stored in it. Due to the fact that |Xp - Xq| >
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 * 2^(nbits - 100) must be satisfied Xp and Xq are generated using the
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 * previous function and supplied as input.
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 */
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int BN_X931_generate_prime_ex(BIGNUM *p, BIGNUM *p1, BIGNUM *p2,
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                              BIGNUM *Xp1, BIGNUM *Xp2,
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                              const BIGNUM *Xp,
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                              const BIGNUM *e, BN_CTX *ctx, BN_GENCB *cb)
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{
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    int ret = 0;
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    BN_CTX_start(ctx);
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    if (Xp1 == NULL)
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        Xp1 = BN_CTX_get(ctx);
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    if (Xp2 == NULL)
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        Xp2 = BN_CTX_get(ctx);
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    if (Xp1 == NULL || Xp2 == NULL)
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        goto error;
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    if (!BN_priv_rand(Xp1, 101, BN_RAND_TOP_ONE, BN_RAND_BOTTOM_ANY))
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        goto error;
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    if (!BN_priv_rand(Xp2, 101, BN_RAND_TOP_ONE, BN_RAND_BOTTOM_ANY))
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        goto error;
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    if (!BN_X931_derive_prime_ex(p, p1, p2, Xp, Xp1, Xp2, e, ctx, cb))
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        goto error;
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    ret = 1;
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 error:
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    BN_CTX_end(ctx);
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    return ret;
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}
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