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			359 lines
		
	
	
	
		
			9.3 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			359 lines
		
	
	
	
		
			9.3 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
| /*
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|  * Copyright 2000-2019 The OpenSSL Project Authors. All Rights Reserved.
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|  *
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|  * Licensed under the OpenSSL license (the "License").  You may not use
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|  * this file except in compliance with the License.  You can obtain a copy
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|  * in the file LICENSE in the source distribution or at
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|  * https://www.openssl.org/source/license.html
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|  */
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| 
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| #include "internal/cryptlib.h"
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| #include "bn_local.h"
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| 
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| BIGNUM *BN_mod_sqrt(BIGNUM *in, const BIGNUM *a, const BIGNUM *p, BN_CTX *ctx)
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| /*
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|  * Returns 'ret' such that ret^2 == a (mod p), using the Tonelli/Shanks
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|  * algorithm (cf. Henri Cohen, "A Course in Algebraic Computational Number
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|  * Theory", algorithm 1.5.1). 'p' must be prime!
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|  */
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| {
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|     BIGNUM *ret = in;
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|     int err = 1;
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|     int r;
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|     BIGNUM *A, *b, *q, *t, *x, *y;
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|     int e, i, j;
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| 
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|     if (!BN_is_odd(p) || BN_abs_is_word(p, 1)) {
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|         if (BN_abs_is_word(p, 2)) {
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|             if (ret == NULL)
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|                 ret = BN_new();
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|             if (ret == NULL)
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|                 goto end;
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|             if (!BN_set_word(ret, BN_is_bit_set(a, 0))) {
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|                 if (ret != in)
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|                     BN_free(ret);
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|                 return NULL;
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|             }
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|             bn_check_top(ret);
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|             return ret;
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|         }
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| 
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|         BNerr(BN_F_BN_MOD_SQRT, BN_R_P_IS_NOT_PRIME);
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|         return NULL;
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|     }
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| 
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|     if (BN_is_zero(a) || BN_is_one(a)) {
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|         if (ret == NULL)
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|             ret = BN_new();
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|         if (ret == NULL)
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|             goto end;
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|         if (!BN_set_word(ret, BN_is_one(a))) {
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|             if (ret != in)
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|                 BN_free(ret);
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|             return NULL;
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|         }
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|         bn_check_top(ret);
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|         return ret;
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|     }
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| 
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|     BN_CTX_start(ctx);
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|     A = BN_CTX_get(ctx);
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|     b = BN_CTX_get(ctx);
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|     q = BN_CTX_get(ctx);
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|     t = BN_CTX_get(ctx);
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|     x = BN_CTX_get(ctx);
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|     y = BN_CTX_get(ctx);
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|     if (y == NULL)
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|         goto end;
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| 
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|     if (ret == NULL)
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|         ret = BN_new();
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|     if (ret == NULL)
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|         goto end;
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| 
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|     /* A = a mod p */
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|     if (!BN_nnmod(A, a, p, ctx))
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|         goto end;
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| 
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|     /* now write  |p| - 1  as  2^e*q  where  q  is odd */
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|     e = 1;
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|     while (!BN_is_bit_set(p, e))
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|         e++;
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|     /* we'll set  q  later (if needed) */
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| 
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|     if (e == 1) {
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|         /*-
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|          * The easy case:  (|p|-1)/2  is odd, so 2 has an inverse
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|          * modulo  (|p|-1)/2,  and square roots can be computed
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|          * directly by modular exponentiation.
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|          * We have
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|          *     2 * (|p|+1)/4 == 1   (mod (|p|-1)/2),
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|          * so we can use exponent  (|p|+1)/4,  i.e.  (|p|-3)/4 + 1.
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|          */
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|         if (!BN_rshift(q, p, 2))
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|             goto end;
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|         q->neg = 0;
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|         if (!BN_add_word(q, 1))
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|             goto end;
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|         if (!BN_mod_exp(ret, A, q, p, ctx))
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|             goto end;
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|         err = 0;
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|         goto vrfy;
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|     }
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| 
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|     if (e == 2) {
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|         /*-
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|          * |p| == 5  (mod 8)
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|          *
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|          * In this case  2  is always a non-square since
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|          * Legendre(2,p) = (-1)^((p^2-1)/8)  for any odd prime.
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|          * So if  a  really is a square, then  2*a  is a non-square.
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|          * Thus for
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|          *      b := (2*a)^((|p|-5)/8),
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|          *      i := (2*a)*b^2
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|          * we have
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|          *     i^2 = (2*a)^((1 + (|p|-5)/4)*2)
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|          *         = (2*a)^((p-1)/2)
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|          *         = -1;
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|          * so if we set
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|          *      x := a*b*(i-1),
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|          * then
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|          *     x^2 = a^2 * b^2 * (i^2 - 2*i + 1)
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|          *         = a^2 * b^2 * (-2*i)
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|          *         = a*(-i)*(2*a*b^2)
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|          *         = a*(-i)*i
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|          *         = a.
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|          *
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|          * (This is due to A.O.L. Atkin,
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|          * Subject: Square Roots and Cognate Matters modulo p=8n+5.
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|          * URL: https://listserv.nodak.edu/cgi-bin/wa.exe?A2=ind9211&L=NMBRTHRY&P=4026
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|          * November 1992.)
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|          */
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| 
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|         /* t := 2*a */
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|         if (!BN_mod_lshift1_quick(t, A, p))
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|             goto end;
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| 
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|         /* b := (2*a)^((|p|-5)/8) */
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|         if (!BN_rshift(q, p, 3))
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|             goto end;
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|         q->neg = 0;
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|         if (!BN_mod_exp(b, t, q, p, ctx))
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|             goto end;
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| 
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|         /* y := b^2 */
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|         if (!BN_mod_sqr(y, b, p, ctx))
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|             goto end;
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| 
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|         /* t := (2*a)*b^2 - 1 */
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|         if (!BN_mod_mul(t, t, y, p, ctx))
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|             goto end;
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|         if (!BN_sub_word(t, 1))
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|             goto end;
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| 
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|         /* x = a*b*t */
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|         if (!BN_mod_mul(x, A, b, p, ctx))
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|             goto end;
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|         if (!BN_mod_mul(x, x, t, p, ctx))
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|             goto end;
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| 
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|         if (!BN_copy(ret, x))
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|             goto end;
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|         err = 0;
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|         goto vrfy;
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|     }
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| 
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|     /*
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|      * e > 2, so we really have to use the Tonelli/Shanks algorithm. First,
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|      * find some y that is not a square.
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|      */
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|     if (!BN_copy(q, p))
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|         goto end;               /* use 'q' as temp */
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|     q->neg = 0;
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|     i = 2;
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|     do {
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|         /*
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|          * For efficiency, try small numbers first; if this fails, try random
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|          * numbers.
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|          */
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|         if (i < 22) {
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|             if (!BN_set_word(y, i))
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|                 goto end;
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|         } else {
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|             if (!BN_priv_rand(y, BN_num_bits(p), 0, 0))
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|                 goto end;
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|             if (BN_ucmp(y, p) >= 0) {
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|                 if (!(p->neg ? BN_add : BN_sub) (y, y, p))
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|                     goto end;
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|             }
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|             /* now 0 <= y < |p| */
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|             if (BN_is_zero(y))
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|                 if (!BN_set_word(y, i))
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|                     goto end;
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|         }
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| 
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|         r = BN_kronecker(y, q, ctx); /* here 'q' is |p| */
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|         if (r < -1)
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|             goto end;
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|         if (r == 0) {
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|             /* m divides p */
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|             BNerr(BN_F_BN_MOD_SQRT, BN_R_P_IS_NOT_PRIME);
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|             goto end;
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|         }
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|     }
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|     while (r == 1 && ++i < 82);
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| 
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|     if (r != -1) {
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|         /*
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|          * Many rounds and still no non-square -- this is more likely a bug
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|          * than just bad luck. Even if p is not prime, we should have found
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|          * some y such that r == -1.
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|          */
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|         BNerr(BN_F_BN_MOD_SQRT, BN_R_TOO_MANY_ITERATIONS);
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|         goto end;
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|     }
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| 
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|     /* Here's our actual 'q': */
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|     if (!BN_rshift(q, q, e))
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|         goto end;
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| 
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|     /*
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|      * Now that we have some non-square, we can find an element of order 2^e
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|      * by computing its q'th power.
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|      */
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|     if (!BN_mod_exp(y, y, q, p, ctx))
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|         goto end;
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|     if (BN_is_one(y)) {
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|         BNerr(BN_F_BN_MOD_SQRT, BN_R_P_IS_NOT_PRIME);
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|         goto end;
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|     }
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| 
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|     /*-
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|      * Now we know that (if  p  is indeed prime) there is an integer
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|      * k,  0 <= k < 2^e,  such that
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|      *
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|      *      a^q * y^k == 1   (mod p).
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|      *
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|      * As  a^q  is a square and  y  is not,  k  must be even.
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|      * q+1  is even, too, so there is an element
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|      *
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|      *     X := a^((q+1)/2) * y^(k/2),
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|      *
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|      * and it satisfies
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|      *
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|      *     X^2 = a^q * a     * y^k
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|      *         = a,
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|      *
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|      * so it is the square root that we are looking for.
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|      */
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| 
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|     /* t := (q-1)/2  (note that  q  is odd) */
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|     if (!BN_rshift1(t, q))
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|         goto end;
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| 
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|     /* x := a^((q-1)/2) */
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|     if (BN_is_zero(t)) {        /* special case: p = 2^e + 1 */
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|         if (!BN_nnmod(t, A, p, ctx))
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|             goto end;
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|         if (BN_is_zero(t)) {
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|             /* special case: a == 0  (mod p) */
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|             BN_zero(ret);
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|             err = 0;
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|             goto end;
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|         } else if (!BN_one(x))
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|             goto end;
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|     } else {
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|         if (!BN_mod_exp(x, A, t, p, ctx))
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|             goto end;
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|         if (BN_is_zero(x)) {
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|             /* special case: a == 0  (mod p) */
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|             BN_zero(ret);
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|             err = 0;
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|             goto end;
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|         }
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|     }
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| 
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|     /* b := a*x^2  (= a^q) */
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|     if (!BN_mod_sqr(b, x, p, ctx))
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|         goto end;
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|     if (!BN_mod_mul(b, b, A, p, ctx))
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|         goto end;
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| 
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|     /* x := a*x    (= a^((q+1)/2)) */
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|     if (!BN_mod_mul(x, x, A, p, ctx))
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|         goto end;
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| 
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|     while (1) {
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|         /*-
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|          * Now  b  is  a^q * y^k  for some even  k  (0 <= k < 2^E
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|          * where  E  refers to the original value of  e,  which we
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|          * don't keep in a variable),  and  x  is  a^((q+1)/2) * y^(k/2).
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|          *
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|          * We have  a*b = x^2,
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|          *    y^2^(e-1) = -1,
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|          *    b^2^(e-1) = 1.
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|          */
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| 
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|         if (BN_is_one(b)) {
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|             if (!BN_copy(ret, x))
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|                 goto end;
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|             err = 0;
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|             goto vrfy;
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|         }
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| 
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|         /* find smallest  i  such that  b^(2^i) = 1 */
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|         i = 1;
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|         if (!BN_mod_sqr(t, b, p, ctx))
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|             goto end;
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|         while (!BN_is_one(t)) {
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|             i++;
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|             if (i == e) {
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|                 BNerr(BN_F_BN_MOD_SQRT, BN_R_NOT_A_SQUARE);
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|                 goto end;
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|             }
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|             if (!BN_mod_mul(t, t, t, p, ctx))
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|                 goto end;
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|         }
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| 
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|         /* t := y^2^(e - i - 1) */
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|         if (!BN_copy(t, y))
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|             goto end;
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|         for (j = e - i - 1; j > 0; j--) {
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|             if (!BN_mod_sqr(t, t, p, ctx))
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|                 goto end;
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|         }
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|         if (!BN_mod_mul(y, t, t, p, ctx))
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|             goto end;
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|         if (!BN_mod_mul(x, x, t, p, ctx))
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|             goto end;
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|         if (!BN_mod_mul(b, b, y, p, ctx))
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|             goto end;
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|         e = i;
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|     }
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| 
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|  vrfy:
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|     if (!err) {
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|         /*
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|          * verify the result -- the input might have been not a square (test
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|          * added in 0.9.8)
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|          */
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| 
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|         if (!BN_mod_sqr(x, ret, p, ctx))
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|             err = 1;
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| 
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|         if (!err && 0 != BN_cmp(x, A)) {
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|             BNerr(BN_F_BN_MOD_SQRT, BN_R_NOT_A_SQUARE);
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|             err = 1;
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|         }
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|     }
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| 
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|  end:
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|     if (err) {
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|         if (ret != in)
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|             BN_clear_free(ret);
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|         ret = NULL;
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|     }
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|     BN_CTX_end(ctx);
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|     bn_check_top(ret);
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|     return ret;
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| }
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